在Java中比较两个ByteBuffers的内容以检查相等性的最简单方法是什么？
在Java中比较两个ByteBuffers的内容以检查相等性的最简单方法是什么？
你可以检查一下 equals() 方法也是。
判断此缓冲区是否等于另一个对象。
两个字节的缓冲区是相等的，当且仅当
- 它们具有相同的元素类型，
- 它们具有相同数量的剩余元素，并且
- 与其起始位置无关地考虑的两个剩余元素序列是逐点相等的。
字节缓冲区不等于任何其他类型的对象。
或者，用 JDK / 11，还有另一种比较方式 ByteBuffer 和另外一个。主要关注于找到两者之间不匹配的API可用作 -
int mismatchBetweenTwoBuffers = byteBuffer1.mismatch(byteBuffer2);
if(mismatchBetweenTwoBuffers == -1) {
System.out.println("The buffers are equal!");
} else {
System.out.println("The buffers are mismatched at - " + mismatchBetweenTwoBuffers);
}
其文件如下：
/**
* Finds and returns the relative index of the first mismatch between this
* buffer and a given buffer. The index is relative to the
* {@link #position() position} of each buffer and will be in the range of
* 0 (inclusive) up to the smaller of the {@link #remaining() remaining}
* elements in each buffer (exclusive).
*
* <p> If the two buffers share a common prefix then the returned index is
* the length of the common prefix and it follows that there is a mismatch
* between the two buffers at that index within the respective buffers.
* If one buffer is a proper prefix of the other then the returned index is
* the smaller of the remaining elements in each buffer, and it follows that
* the index is only valid for the buffer with the larger number of
* remaining elements.
* Otherwise, there is no mismatch.
*
* @return The relative index of the first mismatch between this and the
* given buffer, otherwise -1 if no mismatch.
*
* @since 11
*/
public int mismatch(ByteBuffer that)