好的，我觉得我得到的超级棒 does 独立。基本上在Devise中，如果 Users::RegistrationsController < Devise::RegistrationsController，然后在任何行动，有一个 super 将首先在父级中调用相同命名操作的逻辑 Devise::RegistrationsController在此之前打电话给你写的。
换一种说法...
class Devise::RegistrationsController
def new
puts "this is in the parent controller"
end
end
class Users::RegistrationsController < Devise::RegistrationsController
def new
super
puts "this is in the child controller"
end
end
# Output if users#new is run would be:
# => "this is in the parent controller"
# => "this is in the child controller"
# If super were reversed, and the code looked like this
# class Users::RegistrationsController < Devise::RegistrationsController
# def new
# puts "this is in the child controller"
# super
# end
# end
# Then output if users#new is run would be:
# => "this is in the child controller"
# => "this is in the parent controller"
我很好奇的是，我看到有些人这样做：
class Users::RegistrationsController < Devise::RegistrationsController
def new
super do |user|
puts "something"
end
end
end
我很难把头包裹起来 do block 正在完成。在我的例子中，在创建资源（用户）之后，我想在该资源（用户）上调用另一个方法。
当前代码：
class Users::RegistrationsController < Devise::RegistrationsController
def new
super do |user|
user.charge_and_save_customer
puts user.inspect
end
end
end
我只是想知道这与做的有什么不同：
class Users::RegistrationsController < Devise::RegistrationsController
def new
super
resource.charge_and_save_customer
puts resource.inspect
end
end
如果它有用，我已经包括了父母 Devise::RegistrationsController 代码如下：
def new
build_resource({})
set_minimum_password_length
yield resource if block_given?
respond_with self.resource
end