这个问题在这里已有答案:
- 子集一个2D numpy数组 4个答案
2179
2018-06-12 01:15
起源
答案:
我不完全确定你想要什么,但也许 ix_
有助于?我想我已经看到过那些了解numpy的人比我在类似环境中使用它的人更多。
>>> from numpy import array, arange, ix_
>>> a = arange(25).reshape(5,5)
>>> Xinds = array([1,2,3])
>>> Yinds = array([1,2,3])
>>> a
array([[ 0, 1, 2, 3, 4],
[ 5, 6, 7, 8, 9],
[10, 11, 12, 13, 14],
[15, 16, 17, 18, 19],
[20, 21, 22, 23, 24]])
>>> a[ix_(Xinds, Yinds)]
array([[ 6, 7, 8],
[11, 12, 13],
[16, 17, 18]])
>>> a[ix_(Xinds+1, Yinds)]
array([[11, 12, 13],
[16, 17, 18],
[21, 22, 23]])
>>> Y2inds = array([1,3,4])
>>> a[ix_(Xinds, Y2inds)]
array([[ 6, 8, 9],
[11, 13, 14],
[16, 18, 19]])
>>> a[ix_(Xinds, Y2inds-1)]
array([[ 5, 7, 8],
[10, 12, 13],
[15, 17, 18]])
13
2018-06-12 01:32
这似乎是我正在寻找的。谢谢。 - lnmaurer
答案:
我不完全确定你想要什么,但也许 ix_
有助于?我想我已经看到过那些了解numpy的人比我在类似环境中使用它的人更多。
>>> from numpy import array, arange, ix_
>>> a = arange(25).reshape(5,5)
>>> Xinds = array([1,2,3])
>>> Yinds = array([1,2,3])
>>> a
array([[ 0, 1, 2, 3, 4],
[ 5, 6, 7, 8, 9],
[10, 11, 12, 13, 14],
[15, 16, 17, 18, 19],
[20, 21, 22, 23, 24]])
>>> a[ix_(Xinds, Yinds)]
array([[ 6, 7, 8],
[11, 12, 13],
[16, 17, 18]])
>>> a[ix_(Xinds+1, Yinds)]
array([[11, 12, 13],
[16, 17, 18],
[21, 22, 23]])
>>> Y2inds = array([1,3,4])
>>> a[ix_(Xinds, Y2inds)]
array([[ 6, 8, 9],
[11, 13, 14],
[16, 18, 19]])
>>> a[ix_(Xinds, Y2inds-1)]
array([[ 5, 7, 8],
[10, 12, 13],
[15, 17, 18]])
13
2018-06-12 01:32
这似乎是我正在寻找的。谢谢。 - lnmaurer