问题 结合开放时间相似的日子


我如何在PHP中编写一个函数(使用CodeIgniter)来合并具有类似商店营业时间的日子。例如,如果我们有:

Mon 9am-5pm
Tue 9am-5pm
Wed 9am-5pm
Thu 9am-5pm
Fri 9am-5pm
Sat 9am-7pm
Sun 9am-7pm

我希望代码将其简化为:

Mon-Fri 9am-5pm
Sat-Sun 9am-7pm

如果没有if / else或case ifs的长列表,我该怎么做?我正在使用CodeIgniter ..


5859
2018-05-06 05:03


起源

你在哪里保持defs?在一个数组中,以天为键,小时为值? - Majid Fouladpour


答案:


<?php
$openHours = array(
    'Mon' => '9am-5pm',
    'Tue' => '9am-5pm',
    'Wed' => '9am-9pm',
    'Thu' => '9am-5pm',
    'Fri' => '9am-5pm',
    'Sat' => '9am-7pm',
    'Sun' => '9am-7pm'
);

$summaries = array();
foreach ($openHours as $day => $hours) {
    if (count($summaries) === 0) {
        $current = false;
    } else {
        $current = &$summaries[count($summaries) - 1];
    }
    if ($current === false || $current['hours'] !== $hours) {
        $summaries[] = array('hours' => $hours, 'days' => array($day));
    } else {
        $current['days'][] = $day;
    }
}

foreach ($summaries as $summary) {
    if (count($summary['days']) === 1) {
        echo reset($summary['days']) . ' ' . $summary['hours'] . PHP_EOL;
    } else {
        echo reset($summary['days']) . '-' . end($summary['days']) . ' ' . $summary['hours'] . PHP_EOL;
    }
}

键盘示例


11
2018-05-06 08:55



做得很好。您可以简单地替换整个if / else语句 $summary[$hours][] = $day;。 - Austin
当他们决定在周三晚些时候保持开放时会发生什么? - gilly3
嗯,实际上这会弄乱结果 - peaceman
我更新了解决方案 - peaceman