我目前使用如下方式将单个对象上传到S3：
var options = {
Bucket: bucket,
Key: s3Path,
Body: body,
ACL: s3FilePermissions
};
S3.putObject(options,
function (err, data) {
//console.log(data);
});
但是当我有一个大型资源文件夹时，我使用了 AWS CLI 工具。
我想知道，是否有一种原生方式与aws sdk做同样的事情（将整个文件夹上传到s3）？
老派递归的方式我匆匆忙忙地掀起。仅使用核心节点模块和标准AWS sdk。
var AWS = require('aws-sdk');
var path = require("path");
var fs = require('fs');
const uploadDir = function(s3Path, bucketName) {
let s3 = new AWS.S3();
function walkSync(currentDirPath, callback) {
fs.readdirSync(currentDirPath).forEach(function (name) {
var filePath = path.join(currentDirPath, name);
var stat = fs.statSync(filePath);
if (stat.isFile()) {
callback(filePath, stat);
} else if (stat.isDirectory()) {
walkSync(filePath, callback);
}
});
}
walkSync(s3Path, function(filePath, stat) {
let bucketPath = filePath.substring(s3Path.length+1);
let params = {Bucket: bucketName, Key: bucketPath, Body: fs.readFileSync(filePath) };
s3.putObject(params, function(err, data) {
if (err) {
console.log(err)
} else {
console.log('Successfully uploaded '+ bucketPath +' to ' + bucketName);
}
});
});
};
uploadDir("path to your folder", "your bucket name");
特别感谢Ali来自 这个帖子 帮助获取文件名
前几天我只是在考虑这个问题，并且正在考虑这样的事情：
...
var async = require('async'),
fs = require('fs'),
path = require("path");
var directoryName = './test',
directoryPath = path.resolve(directoryName);
var files = fs.readdirSync(directoryPath);
async.map(files, function (f, cb) {
var filePath = path.join(directoryPath, f);
var options = {
Bucket: bucket,
Key: s3Path,
Body: fs.readFileSync(filePath),
ACL: s3FilePermissions
};
S3.putObject(options, cb);
}, function (err, results) {
if (err) console.error(err);
console.log(results);
});
老派递归的方式我匆匆忙忙地掀起。仅使用核心节点模块和标准AWS sdk。
var AWS = require('aws-sdk');
var path = require("path");
var fs = require('fs');
const uploadDir = function(s3Path, bucketName) {
let s3 = new AWS.S3();
function walkSync(currentDirPath, callback) {
fs.readdirSync(currentDirPath).forEach(function (name) {
var filePath = path.join(currentDirPath, name);
var stat = fs.statSync(filePath);
if (stat.isFile()) {
callback(filePath, stat);
} else if (stat.isDirectory()) {
walkSync(filePath, callback);
}
});
}
walkSync(s3Path, function(filePath, stat) {
let bucketPath = filePath.substring(s3Path.length+1);
let params = {Bucket: bucketName, Key: bucketPath, Body: fs.readFileSync(filePath) };
s3.putObject(params, function(err, data) {
if (err) {
console.log(err)
} else {
console.log('Successfully uploaded '+ bucketPath +' to ' + bucketName);
}
});
});
};
uploadDir("path to your folder", "your bucket name");
特别感谢Ali来自 这个帖子 帮助获取文件名
前几天我只是在考虑这个问题，并且正在考虑这样的事情：
...
var async = require('async'),
fs = require('fs'),
path = require("path");
var directoryName = './test',
directoryPath = path.resolve(directoryName);
var files = fs.readdirSync(directoryPath);
async.map(files, function (f, cb) {
var filePath = path.join(directoryPath, f);
var options = {
Bucket: bucket,
Key: s3Path,
Body: fs.readFileSync(filePath),
ACL: s3FilePermissions
};
S3.putObject(options, cb);
}, function (err, results) {
if (err) console.error(err);
console.log(results);
});
你可以尝试一下 节点S3-客户。
更新：在npm上可用 这里
从同步目录到s3 文档：
更新：添加了客户端inialization代码。
var client = s3.createClient({
maxAsyncS3: 20, // this is the default
s3RetryCount: 3, // this is the default
s3RetryDelay: 1000, // this is the default
multipartUploadThreshold: 20971520, // this is the default (20 MB)
multipartUploadSize: 15728640, // this is the default (15 MB)
s3Options: {
accessKeyId: "YOUR ACCESS KEY",
secretAccessKey: "YOUR SECRET ACCESS KEY"
}
});
var params = {
localDir: "some/local/dir",
deleteRemoved: true, // default false, whether to remove s3 objects
// that have no corresponding local file.
s3Params: {
Bucket: "s3 bucket name",
Prefix: "some/remote/dir/",
// other options supported by putObject, except Body and ContentLength.
// See: http://docs.aws.amazon.com/AWSJavaScriptSDK/latest/AWS/S3.html#putObject-property
},
};
var uploader = client.uploadDir(params);
uploader.on('error', function(err) {
console.error("unable to sync:", err.stack);
});
uploader.on('progress', function() {
console.log("progress", uploader.progressAmount, uploader.progressTotal);
});
uploader.on('end', function() {
console.log("done uploading");
});