所以，我有这样的情况。
class A(object):
def foo(self, call_from):
print "foo from A, call from %s" % call_from
class B(object):
def foo(self, call_from):
print "foo from B, call from %s" % call_from
class C(object):
def foo(self, call_from):
print "foo from C, call from %s" % call_from
class D(A, B, C):
def foo(self):
print "foo from D"
super(D, self).foo("D")
d = D()
d.foo()
代码的结果是
foo from D
foo from A, call from D
我想调用所有父方法，在这种情况下，foo方法，来自 D 没有在父类中使用super的类 A。我只想打电话给超级 D 类。该 A， B，和 C class就像mixin类一样，我想调用所有foo方法 D。我怎样才能做到这一点？
您可以使用 __bases__ 喜欢这个
class D(A, B, C):
def foo(self):
print "foo from D"
for cls in D.__bases__:
cls().foo("D")
通过此更改，输出将是
foo from D
foo from A, call from D
foo from B, call from D
foo from C, call from D
您可以使用 __bases__ 喜欢这个
class D(A, B, C):
def foo(self):
print "foo from D"
for cls in D.__bases__:
cls().foo("D")
通过此更改，输出将是
foo from D
foo from A, call from D
foo from B, call from D
foo from C, call from D
加 super() 除了以外在其他课程中打电话 C。因为D的MRO是
>>> D.__mro__
(<class '__main__.D'>, <class '__main__.A'>, <class '__main__.B'>, <class '__main__.C'>, <type 'object'>)
你不需要超级电话 C。
码：
class A(object):
def foo(self, call_from):
print "foo from A, call from %s" % call_from
super(A,self).foo('A')
class B(object):
def foo(self, call_from):
print "foo from B, call from %s" % call_from
super(B, self).foo('B')
class C(object):
def foo(self, call_from):
print "foo from C, call from %s" % call_from
class D(A, B, C):
def foo(self):
print "foo from D"
super(D, self).foo("D")
d = D()
d.foo()
输出：
foo from D
foo from A, call from D
foo from B, call from A
foo from C, call from B